is happening @ the Hideout Theatre...
...and YOU are invited to perform in it.
For those who don't know, "Same Year's Eve" is the BEST show of the year. BEST because the Austin Improv community is all in one spot -- on stage at almost the same time -- even when we try to break into groups.
It's a bit of a mess artistically speaking, BUT! as a community event, it is awesome.
It also ends up being a fun reunion with all the Austin ex-pats coming home to join in the show.
It's a huge cast -- essentially a 2 hour improv jam-show broken into three (35-40 min) acts:
Act 1 = shortform games (8:00-8:35pm)
Act 2 = montage scenes (8:40-9:15pm)
Act 3 = musical narrative (9:20-10:00pm)
If you want to play in the show, you show up at 7pm to grab a number out of the hat. Based on the number you draw, you are divided into one of the three sets. The groups then break out to practice and warm up.
It's our hope that this will all work like it has in the past. However, the scene continues to grow. If we have an INSANE turnout, we may have to limit the number of cast via a lottery system. To that end, we're asking that you show up by no later than 7:15pm.
There will be mixing and mingling afterwards, with potluck treats, music & dancing, a live performance of Manateeman's Wizard Album, beer from Orf Brewing, and there's always a final count-down-to-Midnight to ring in the "Same Year" with too many toasts.
All this goes down on Dec. 30th at The Hideout. All students, improvisers, past or present, from any of the theaters (or from anywhere) are invite to perform.
Spread the word.
Who's in? Any questions?
